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Solving integrals/ sqrt(x^2-2x+5)

Integral of sqrt(x^2-2x+5) dx

Limits of integration:

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Piecewise:

The solution

You have entered [src] 
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∫01(x2−2x)+5 dx\int\limits_{0}^{1} \sqrt{\left(x^{2} - 2 x\right) + 5}\, dx 
Integral(sqrt(x^2 - 2*x + 5), (x, 0, 1))
The answer [src] 
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∫01x2−2x+5 dx\int\limits_{0}^{1} \sqrt{x^{2} - 2 x + 5}\, dx 
=
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∫01x2−2x+5 dx\int\limits_{0}^{1} \sqrt{x^{2} - 2 x + 5}\, dx 
Integral(sqrt(5 + x^2 - 2*x), (x, 0, 1))
Numerical answer [src] 
2.0804576388691
2.0804576388691

    Use the examples entering the upper and lower limits of integration.

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