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- Improper integral
- Double Integral
- Triple Integral
- Curvilinear integral
- Derivative Step by Step
- Differential equations Step by Step
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How to use it?
- Integral of d{x}:
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Integral of 1/(x^2+2*x+5)
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Integral of 1/sqrt(x^2+1)
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Integral of 1/(x+1)^3
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Integral of 3^(2*x)
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Identical expressions
- sqrt(one -x/ two -y/ two)
- square root of (1 minus x divide by 2 minus y divide by 2)
- square root of (one minus x divide by two minus y divide by two)
- √(1-x/2-y/2)
- sqrt1-x/2-y/2
- sqrt(1-x divide by 2-y divide by 2)
- sqrt(1-x/2-y/2)dx
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Similar expressions
- sqrt(1+x/2-y/2)
- sqrt(1-x/2+y/2)
Integral of sqrt(1-x/2-y/2) dx
The solution
You have entered
[src]
1 / | | ___________ | / x y | / 1 - - - - dx | \/ 2 2 | / 0
$$\int\limits_{0}^{1} \sqrt{- \frac{x}{2} - \frac{y}{2} + 1}\, dx$$
Integral(sqrt(1 - x/2 - y/2), (x, 0, 1))
The answer (Indefinite)
[src]
/ 3/2 | / x y\ | ___________ 4*|1 - - - -| | / x y \ 2 2/ | / 1 - - - - dx = C - ---------------- | \/ 2 2 3 | /
$$-{{4\,\left(-{{y}\over{2}}-{{x}\over{2}}+1\right)^{{{3}\over{2}}}
}\over{3}}$$
The answer
[src]
3/2 3/2
/1 y\ / y\
4*|- - -| 4*|1 - -|
\2 2/ \ 2/
- ------------ + ------------
3 3
$${{\sqrt{1-y}\,\left(2\,y-2\right)}\over{3\,\sqrt{2}}}-{{\sqrt{2-y}
\,\left(2\,y-4\right)}\over{3\,\sqrt{2}}}$$
=
=
3/2 3/2
/1 y\ / y\
4*|- - -| 4*|1 - -|
\2 2/ \ 2/
- ------------ + ------------
3 3
$$- \frac{4 \left(\frac{1}{2} - \frac{y}{2}\right)^{\frac{3}{2}}}{3} + \frac{4 \left(1 - \frac{y}{2}\right)^{\frac{3}{2}}}{3}$$
Use the examples entering the upper and lower limits of integration.