Integral of (6-x)/2 dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫26−xdx=2∫(6−x)dx
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Integrate term-by-term:
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The integral of a constant is the constant times the variable of integration:
∫6dx=6x
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x)dx=−∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: −2x2
The result is: −2x2+6x
So, the result is: −4x2+3x
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Now simplify:
4x(12−x)
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Add the constant of integration:
4x(12−x)+constant
The answer is:
4x(12−x)+constant
The answer (Indefinite)
[src]
/
| 2
| 6 - x x
| ----- dx = C + 3*x - --
| 2 4
|
/
6x−4x2
The graph
Use the examples entering the upper and lower limits of integration.