1 / | | / pi\ | sin|x - --| dx | \ 3 / | / 0
Integral(sin(x - pi/3), (x, 0, 1))
Let .
Then let and substitute :
The integral of sine is negative cosine:
Now substitute back in:
Now simplify:
Add the constant of integration:
The answer is:
/ | | / pi\ / pi\ | sin|x - --| dx = C - cos|x - --| | \ 3 / \ 3 / | /
1 / pi\ - - sin|1 + --| 2 \ 6 /
=
1 / pi\ - - sin|1 + --| 2 \ 6 /
1/2 - sin(1 + pi/6)
Use the examples entering the upper and lower limits of integration.