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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of x^(-1/2)
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Integral of 1/sqrt(1+u^2)
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Integral of x^4lnx
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Integral of x*dx/(x^2-1)
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Identical expressions
- (sinx)/(cos^(two)x)
- ( sinus of x) divide by ( co sinus of e of to the power of (2)x)
- ( sinus of x) divide by ( co sinus of e of to the power of (two)x)
- (sinx)/(cos(2)x)
- sinx/cos2x
- sinx/cos^2x
- (sinx) divide by (cos^(2)x)
- (sinx)/(cos^(2)x)dx
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Similar expressions
- sinx/cos^2xdx
- xsinx/cos^2x
Integral of (sinx)/(cos^(2)x) dx
The solution
You have entered
[src]
1 / | | sin(x) | ------- dx | 2 | cos (x) | / 0
$$\int\limits_{0}^{1} \frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)}}\, dx$$
Integral(sin(x)/cos(x)^2, (x, 0, 1))
The answer (Indefinite)
[src]
/ | | sin(x) 1 | ------- dx = C + ------ | 2 cos(x) | cos (x) | /
$$\int \frac{\sin{\left(x \right)}}{\cos^{2}{\left(x \right)}}\, dx = C + \frac{1}{\cos{\left(x \right)}}$$
The graph
The answer
[src]
1
-1 + ------
cos(1)
$$-1 + \frac{1}{\cos{\left(1 \right)}}$$
=
=
1
-1 + ------
cos(1)
$$-1 + \frac{1}{\cos{\left(1 \right)}}$$
-1 + 1/cos(1)
Use the examples entering the upper and lower limits of integration.