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Integral of x^n*e^(-x) dx

Limits of integration:

from to
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
  1          
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 |   n  -x   
 |  x *E   dx
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0            
$$\int\limits_{0}^{1} e^{- x} x^{n}\, dx$$
Integral(x^n*E^(-x), (x, 0, 1))
Detail solution

    UpperGammaRule(a=-1, e=n, context=E**(-x)*x**n, symbol=x)

  1. Add the constant of integration:


The answer is:

The answer (Indefinite) [src]
  /                               
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 |  n  -x                         
 | x *E   dx = C - Gamma(1 + n, x)
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/                                 
$$\int e^{- x} x^{n}\, dx = C - \Gamma\left(n + 1, x\right)$$
The answer [src]
Gamma(1 + n)*lowergamma(1 + n, 1)   n*Gamma(1 + n)*lowergamma(1 + n, 1)
--------------------------------- + -----------------------------------
           Gamma(2 + n)                         Gamma(2 + n)           
$$\frac{n \Gamma\left(n + 1\right) \gamma\left(n + 1, 1\right)}{\Gamma\left(n + 2\right)} + \frac{\Gamma\left(n + 1\right) \gamma\left(n + 1, 1\right)}{\Gamma\left(n + 2\right)}$$
=
=
Gamma(1 + n)*lowergamma(1 + n, 1)   n*Gamma(1 + n)*lowergamma(1 + n, 1)
--------------------------------- + -----------------------------------
           Gamma(2 + n)                         Gamma(2 + n)           
$$\frac{n \Gamma\left(n + 1\right) \gamma\left(n + 1, 1\right)}{\Gamma\left(n + 2\right)} + \frac{\Gamma\left(n + 1\right) \gamma\left(n + 1, 1\right)}{\Gamma\left(n + 2\right)}$$
gamma(1 + n)*lowergamma(1 + n, 1)/gamma(2 + n) + n*gamma(1 + n)*lowergamma(1 + n, 1)/gamma(2 + n)

    Use the examples entering the upper and lower limits of integration.