Integral of sin(sinx)cosx dx
The solution
Detail solution
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Let u=sin(x).
Then let du=cos(x)dx and substitute du:
∫sin(u)du
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The integral of sine is negative cosine:
∫sin(u)du=−cos(u)
Now substitute u back in:
−cos(sin(x))
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Add the constant of integration:
−cos(sin(x))+constant
The answer is:
−cos(sin(x))+constant
The answer (Indefinite)
[src]
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| sin(sin(x))*cos(x) dx = C - cos(sin(x))
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∫sin(sin(x))cos(x)dx=C−cos(sin(x))
The graph
1−cos(sin(1))
=
1−cos(sin(1))
Use the examples entering the upper and lower limits of integration.