Integral of sin(5x+3) dx
The solution
Detail solution
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Let u=5x+3.
Then let du=5dx and substitute 5du:
∫25sin(u)du
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The integral of a constant times a function is the constant times the integral of the function:
∫5sin(u)du=5∫sin(u)du
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The integral of sine is negative cosine:
∫sin(u)du=−cos(u)
So, the result is: −5cos(u)
Now substitute u back in:
−5cos(5x+3)
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Now simplify:
−5cos(5x+3)
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Add the constant of integration:
−5cos(5x+3)+constant
The answer is:
−5cos(5x+3)+constant
The answer (Indefinite)
[src]
/
| cos(5*x + 3)
| sin(5*x + 3) dx = C - ------------
| 5
/
−5cos(5x+3)
The graph
cos(8) cos(3)
- ------ + ------
5 5
5cos3−cos8
=
cos(8) cos(3)
- ------ + ------
5 5
5cos(3)−5cos(8)
Use the examples entering the upper and lower limits of integration.