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sin3x/sinx

Integral of sin3x/sinx dx

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The solution

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  1            
  /            
 |             
 |  sin(3*x)   
 |  -------- dx
 |   sin(x)    
 |             
/              
0              
01sin(3x)sin(x)dx\int\limits_{0}^{1} \frac{\sin{\left(3 x \right)}}{\sin{\left(x \right)}}\, dx
Integral(sin(3*x)/sin(x), (x, 0, 1))
Detail solution
  1. Rewrite the integrand:

    sin(3x)sin(x)=34sin2(x)\frac{\sin{\left(3 x \right)}}{\sin{\left(x \right)}} = 3 - 4 \sin^{2}{\left(x \right)}

  2. Integrate term-by-term:

    1. The integral of a constant is the constant times the variable of integration:

      3dx=3x\int 3\, dx = 3 x

    1. The integral of a constant times a function is the constant times the integral of the function:

      (4sin2(x))dx=4sin2(x)dx\int \left(- 4 \sin^{2}{\left(x \right)}\right)\, dx = - 4 \int \sin^{2}{\left(x \right)}\, dx

      1. Rewrite the integrand:

        sin2(x)=12cos(2x)2\sin^{2}{\left(x \right)} = \frac{1}{2} - \frac{\cos{\left(2 x \right)}}{2}

      2. Integrate term-by-term:

        1. The integral of a constant is the constant times the variable of integration:

          12dx=x2\int \frac{1}{2}\, dx = \frac{x}{2}

        1. The integral of a constant times a function is the constant times the integral of the function:

          (cos(2x)2)dx=cos(2x)dx2\int \left(- \frac{\cos{\left(2 x \right)}}{2}\right)\, dx = - \frac{\int \cos{\left(2 x \right)}\, dx}{2}

          1. Let u=2xu = 2 x.

            Then let du=2dxdu = 2 dx and substitute du2\frac{du}{2}:

            cos(u)2du\int \frac{\cos{\left(u \right)}}{2}\, du

            1. The integral of a constant times a function is the constant times the integral of the function:

              cos(u)du=cos(u)du2\int \cos{\left(u \right)}\, du = \frac{\int \cos{\left(u \right)}\, du}{2}

              1. The integral of cosine is sine:

                cos(u)du=sin(u)\int \cos{\left(u \right)}\, du = \sin{\left(u \right)}

              So, the result is: sin(u)2\frac{\sin{\left(u \right)}}{2}

            Now substitute uu back in:

            sin(2x)2\frac{\sin{\left(2 x \right)}}{2}

          So, the result is: sin(2x)4- \frac{\sin{\left(2 x \right)}}{4}

        The result is: x2sin(2x)4\frac{x}{2} - \frac{\sin{\left(2 x \right)}}{4}

      So, the result is: 2x+sin(2x)- 2 x + \sin{\left(2 x \right)}

    The result is: x+sin(2x)x + \sin{\left(2 x \right)}

  3. Add the constant of integration:

    x+sin(2x)+constantx + \sin{\left(2 x \right)}+ \mathrm{constant}


The answer is:

x+sin(2x)+constantx + \sin{\left(2 x \right)}+ \mathrm{constant}

The answer (Indefinite) [src]
  /                              
 |                               
 | sin(3*x)                      
 | -------- dx = C + x + sin(2*x)
 |  sin(x)                       
 |                               
/                                
sin(3x)sin(x)dx=C+x+sin(2x)\int \frac{\sin{\left(3 x \right)}}{\sin{\left(x \right)}}\, dx = C + x + \sin{\left(2 x \right)}
The graph
0.001.000.100.200.300.400.500.600.700.800.9005
The answer [src]
1 + sin(2)
sin(2)+1\sin{\left(2 \right)} + 1
=
=
1 + sin(2)
sin(2)+1\sin{\left(2 \right)} + 1
1 + sin(2)
Numerical answer [src]
1.90929742682568
1.90929742682568
The graph
Integral of sin3x/sinx dx

    Use the examples entering the upper and lower limits of integration.