Integral of sin2x/sinx dx
The solution
Detail solution
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There are multiple ways to do this integral.
Method #1
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The integral of a constant times a function is the constant times the integral of the function:
∫2cos(x)dx=2∫cos(x)dx
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The integral of cosine is sine:
∫cos(x)dx=sin(x)
So, the result is: 2sin(x)
Method #2
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Rewrite the integrand:
sin(x)sin(2x)=2cos(x)
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The integral of a constant times a function is the constant times the integral of the function:
∫2cos(x)dx=2∫cos(x)dx
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The integral of cosine is sine:
∫cos(x)dx=sin(x)
So, the result is: 2sin(x)
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Add the constant of integration:
2sin(x)+constant
The answer is:
2sin(x)+constant
The answer (Indefinite)
[src]
/
|
| sin(2*x)
| -------- dx = C + 2*sin(x)
| sin(x)
|
/
∫sin(x)sin(2x)dx=C+2sin(x)
The graph
2sin(1)
=
2sin(1)
Use the examples entering the upper and lower limits of integration.