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How to use it?
- Integral of d{x}:
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Integral of 4x
- Integral of sinxsin2xsin3x
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Integral of -7
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Integral of 1/chx
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Identical expressions
- sh(x-y)shx/(chx)^ two
- sh(x minus y)shx divide by (chx) squared
- sh(x minus y)shx divide by (chx) to the power of two
- sh(x-y)shx/(chx)2
- shx-yshx/chx2
- sh(x-y)shx/(chx)²
- sh(x-y)shx/(chx) to the power of 2
- shx-yshx/chx^2
- sh(x-y)shx divide by (chx)^2
- sh(x-y)shx/(chx)^2dx
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Similar expressions
- sh(x+y)shx/(chx)^2
Integral of sh(x-y)shx/(chx)^2 dx
The solution
You have entered
[src]
1 / | | sinh(x - y)*sinh(x) | ------------------- dx | 2 | cosh (x) | / 0
$$\int\limits_{0}^{1} \frac{\sinh{\left(x \right)} \sinh{\left(x - y \right)}}{\cosh^{2}{\left(x \right)}}\, dx$$
Integral(sinh(x - y)*sinh(x)/(cosh(x)^2), (x, 0, 1))
The answer (Indefinite)
[src]
/ / | | | sinh(x - y)*sinh(x) | sinh(x)*sinh(x - y) | ------------------- dx = C + | ------------------- dx | 2 | 2 | cosh (x) | cosh (x) | | / /
$$-{{e^{2\,y}+1}\over{e^{y-2\,x}+e^{y}}}-{{\log \left(e^ {- 2\,x }+1
\right)\,e^ {- y }\,\left(e^{2\,y}-1\right)}\over{2}}+x\,e^ {- y }$$
The answer
[src]
1 / | | sinh(x)*sinh(x - y) | ------------------- dx | 2 | cosh (x) | / 0
$$-{{\left(e^2+1\right)\,\log \left({{e^ {- 1 }\,\left(e^2+1\right)
}\over{2}}\right)\,\sinh y-2\,\cosh y}\over{e^2+1}}$$
=
=
1 / | | sinh(x)*sinh(x - y) | ------------------- dx | 2 | cosh (x) | / 0
$$\int\limits_{0}^{1} \frac{\sinh{\left(x \right)} \sinh{\left(x - y \right)}}{\cosh^{2}{\left(x \right)}}\, dx$$
Use the examples entering the upper and lower limits of integration.