Integral of pi(sqrt(x)e^x)^2 dx
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫π(xex)2dx=π∫(xex)2dx
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Don't know the steps in finding this integral.
But the integral is
4(2x−1)e2x
So, the result is: 4π(2x−1)e2x
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Add the constant of integration:
4π(2x−1)e2x+constant
The answer is:
4π(2x−1)e2x+constant
The answer (Indefinite)
[src]
/
|
| 2 2*x
| / ___ x\ pi*(-1 + 2*x)*e
| pi*\\/ x *e / dx = C + ------------------
| 4
/
4π(2x−1)e2x
The graph
(4e2+41)π
=
4π+4πe2
Use the examples entering the upper and lower limits of integration.