Integral of -1/t dt
The solution
Detail solution
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The integral of a constant times a function is the constant times the integral of the function:
∫(−t1)dt=−∫t1dt
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The integral of t1 is log(t).
So, the result is: −log(t)
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Add the constant of integration:
−log(t)+constant
The answer is:
−log(t)+constant
The answer (Indefinite)
[src]
/
|
| -1
| --- dt = C - log(t)
| t
|
/
∫(−t1)dt=C−log(t)
The graph
Use the examples entering the upper and lower limits of integration.