1 + 2*I
/
|
| 1
| - dz
| z
|
/
1
Integral(1/z, (z, 1, 1 + 2*i))
The integral of is .
Add the constant of integration:
The answer is:
/ | | 1 | - dz = C + log(z) | z | /
log(1 + 2*I)
=
log(1 + 2*I)
log(1 + 2*i)
(0.80471895621705 + 1.10714871779409j)
(0.80471895621705 + 1.10714871779409j)
Use the examples entering the upper and lower limits of integration.