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Integral of e^(-(x^(1/(z+1)))) dx

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$$\int\limits_{0}^{1} e^{- x^{\frac{1}{z + 1}}}\, dx$$
Integral(E^(-x^(1/(z + 1))), (x, 0, 1))
The answer (Indefinite) [src]
  /                                                                                                                                                 
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 |      1                                   /          1  \                             /          1  \                              /          1  \
 |    -----                                 |        -----|                             |        -----|                              |        -----|
 |    z + 1                                 |        1 + z|    2                        |        1 + z|                              |        1 + z|
 |  -x               Gamma(1 + z)*lowergamma\1 + z, x     /   z *Gamma(1 + z)*lowergamma\1 + z, x     /   2*z*Gamma(1 + z)*lowergamma\1 + z, x     /
 | E        dx = C + -------------------------------------- + ----------------------------------------- + ------------------------------------------
 |                                Gamma(2 + z)                               Gamma(2 + z)                                Gamma(2 + z)               
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$$\int e^{- x^{\frac{1}{z + 1}}}\, dx = C + \frac{z^{2} \Gamma\left(z + 1\right) \gamma\left(z + 1, x^{\frac{1}{z + 1}}\right)}{\Gamma\left(z + 2\right)} + \frac{2 z \Gamma\left(z + 1\right) \gamma\left(z + 1, x^{\frac{1}{z + 1}}\right)}{\Gamma\left(z + 2\right)} + \frac{\Gamma\left(z + 1\right) \gamma\left(z + 1, x^{\frac{1}{z + 1}}\right)}{\Gamma\left(z + 2\right)}$$
The answer [src]
                                                           /          1  \                                                                    /          1  \                              /          1  \                                        
                                                           |        -----|                                                                    |        -----|                              |        -----|                                        
                                                           |        1 + z|    2                                      2                        |        1 + z|                              |        1 + z|                                        
Gamma(1 + z)*lowergamma(1 + z, 1)   Gamma(1 + z)*lowergamma\1 + z, 0     /   z *Gamma(1 + z)*lowergamma(1 + z, 1)   z *Gamma(1 + z)*lowergamma\1 + z, 0     /   2*z*Gamma(1 + z)*lowergamma\1 + z, 0     /   2*z*Gamma(1 + z)*lowergamma(1 + z, 1)
--------------------------------- - -------------------------------------- + ------------------------------------ - ----------------------------------------- - ------------------------------------------ + -------------------------------------
           Gamma(2 + z)                          Gamma(2 + z)                            Gamma(2 + z)                              Gamma(2 + z)                                Gamma(2 + z)                               Gamma(2 + z)            
$$\frac{z^{2} \Gamma\left(z + 1\right) \gamma\left(z + 1, 1\right)}{\Gamma\left(z + 2\right)} - \frac{z^{2} \Gamma\left(z + 1\right) \gamma\left(z + 1, 0^{\frac{1}{z + 1}}\right)}{\Gamma\left(z + 2\right)} + \frac{2 z \Gamma\left(z + 1\right) \gamma\left(z + 1, 1\right)}{\Gamma\left(z + 2\right)} - \frac{2 z \Gamma\left(z + 1\right) \gamma\left(z + 1, 0^{\frac{1}{z + 1}}\right)}{\Gamma\left(z + 2\right)} + \frac{\Gamma\left(z + 1\right) \gamma\left(z + 1, 1\right)}{\Gamma\left(z + 2\right)} - \frac{\Gamma\left(z + 1\right) \gamma\left(z + 1, 0^{\frac{1}{z + 1}}\right)}{\Gamma\left(z + 2\right)}$$
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                                                           |        -----|                                                                    |        -----|                              |        -----|                                        
                                                           |        1 + z|    2                                      2                        |        1 + z|                              |        1 + z|                                        
Gamma(1 + z)*lowergamma(1 + z, 1)   Gamma(1 + z)*lowergamma\1 + z, 0     /   z *Gamma(1 + z)*lowergamma(1 + z, 1)   z *Gamma(1 + z)*lowergamma\1 + z, 0     /   2*z*Gamma(1 + z)*lowergamma\1 + z, 0     /   2*z*Gamma(1 + z)*lowergamma(1 + z, 1)
--------------------------------- - -------------------------------------- + ------------------------------------ - ----------------------------------------- - ------------------------------------------ + -------------------------------------
           Gamma(2 + z)                          Gamma(2 + z)                            Gamma(2 + z)                              Gamma(2 + z)                                Gamma(2 + z)                               Gamma(2 + z)            
$$\frac{z^{2} \Gamma\left(z + 1\right) \gamma\left(z + 1, 1\right)}{\Gamma\left(z + 2\right)} - \frac{z^{2} \Gamma\left(z + 1\right) \gamma\left(z + 1, 0^{\frac{1}{z + 1}}\right)}{\Gamma\left(z + 2\right)} + \frac{2 z \Gamma\left(z + 1\right) \gamma\left(z + 1, 1\right)}{\Gamma\left(z + 2\right)} - \frac{2 z \Gamma\left(z + 1\right) \gamma\left(z + 1, 0^{\frac{1}{z + 1}}\right)}{\Gamma\left(z + 2\right)} + \frac{\Gamma\left(z + 1\right) \gamma\left(z + 1, 1\right)}{\Gamma\left(z + 2\right)} - \frac{\Gamma\left(z + 1\right) \gamma\left(z + 1, 0^{\frac{1}{z + 1}}\right)}{\Gamma\left(z + 2\right)}$$
gamma(1 + z)*lowergamma(1 + z, 1)/gamma(2 + z) - gamma(1 + z)*lowergamma(1 + z, 0^(1/(1 + z)))/gamma(2 + z) + z^2*gamma(1 + z)*lowergamma(1 + z, 1)/gamma(2 + z) - z^2*gamma(1 + z)*lowergamma(1 + z, 0^(1/(1 + z)))/gamma(2 + z) - 2*z*gamma(1 + z)*lowergamma(1 + z, 0^(1/(1 + z)))/gamma(2 + z) + 2*z*gamma(1 + z)*lowergamma(1 + z, 1)/gamma(2 + z)

    Use the examples entering the upper and lower limits of integration.