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- Improper integral
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How to use it?
- Integral of d{x}:
- Integral of 1/(x^2+6x-16)
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Integral of arcctg(x)
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Integral of x^3cosxdx
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Integral of tg5x
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Identical expressions
- one /(x^ two +6x- sixteen)
- 1 divide by (x squared plus 6x minus 16)
- one divide by (x to the power of two plus 6x minus sixteen)
- 1/(x2+6x-16)
- 1/x2+6x-16
- 1/(x²+6x-16)
- 1/(x to the power of 2+6x-16)
- 1/x^2+6x-16
- 1 divide by (x^2+6x-16)
- 1/(x^2+6x-16)dx
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Similar expressions
- 1/(x^2-6x-16)
- 1/(x^2+6x+16)
Integral of 1/(x^2+6x-16) dx
The solution
You have entered
[src]
oo / | | 1 | ------------- dx | 2 | x + 6*x - 16 | / 10
$$\int\limits_{10}^{\infty} \frac{1}{\left(x^{2} + 6 x\right) - 16}\, dx$$
Integral(1/(x^2 + 6*x - 16), (x, 10, oo))
The answer (Indefinite)
[src]
/ | | 1 log(8 + x) log(-2 + x) | ------------- dx = C - ---------- + ----------- | 2 10 10 | x + 6*x - 16 | /
$$\int \frac{1}{\left(x^{2} + 6 x\right) - 16}\, dx = C + \frac{\log{\left(x - 2 \right)}}{10} - \frac{\log{\left(x + 8 \right)}}{10}$$
The graph
The answer
[src]
log(8) log(18)
- ------ + -------
10 10
$$- \frac{\log{\left(8 \right)}}{10} + \frac{\log{\left(18 \right)}}{10}$$
=
=
log(8) log(18)
- ------ + -------
10 10
$$- \frac{\log{\left(8 \right)}}{10} + \frac{\log{\left(18 \right)}}{10}$$
-log(8)/10 + log(18)/10
Use the examples entering the upper and lower limits of integration.