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- Improper integral
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How to use it?
- Integral of d{x}:
- Integral of 1/(x^2-8x-9)
- Integral of cos(npix/l)
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Integral of e^(5x+7)*dx
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Integral of sin(4x)cos(4x)dx
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Identical expressions
- one /(x^ two -8x- nine)
- 1 divide by (x squared minus 8x minus 9)
- one divide by (x to the power of two minus 8x minus nine)
- 1/(x2-8x-9)
- 1/x2-8x-9
- 1/(x²-8x-9)
- 1/(x to the power of 2-8x-9)
- 1/x^2-8x-9
- 1 divide by (x^2-8x-9)
- 1/(x^2-8x-9)dx
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Similar expressions
- 1/(x^2-8x+9)
- 1/(x^2+8x-9)
Integral of 1/(x^2-8x-9) dx
The solution
You have entered
[src]
1 / | | 1 | ------------ dx | 2 | x - 8*x - 9 | / 0
$$\int\limits_{0}^{1} \frac{1}{\left(x^{2} - 8 x\right) - 9}\, dx$$
Integral(1/(x^2 - 8*x - 9), (x, 0, 1))
The answer (Indefinite)
[src]
/ | | 1 log(1 + x) log(-9 + x) | ------------ dx = C - ---------- + ----------- | 2 10 10 | x - 8*x - 9 | /
$$\int \frac{1}{\left(x^{2} - 8 x\right) - 9}\, dx = C + \frac{\log{\left(x - 9 \right)}}{10} - \frac{\log{\left(x + 1 \right)}}{10}$$
The graph
The answer
[src]
log(2) log(9) log(8)
- ------ - ------ + ------
10 10 10
$$- \frac{\log{\left(9 \right)}}{10} - \frac{\log{\left(2 \right)}}{10} + \frac{\log{\left(8 \right)}}{10}$$
=
=
log(2) log(9) log(8)
- ------ - ------ + ------
10 10 10
$$- \frac{\log{\left(9 \right)}}{10} - \frac{\log{\left(2 \right)}}{10} + \frac{\log{\left(8 \right)}}{10}$$
-log(2)/10 - log(9)/10 + log(8)/10
Use the examples entering the upper and lower limits of integration.