Integral of 1/(x^(1/2)+1) dx
The solution
Detail solution
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Let u=x.
Then let du=2xdx and substitute 2du:
∫u+12udu
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The integral of a constant times a function is the constant times the integral of the function:
∫u+1udu=2∫u+1udu
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Rewrite the integrand:
u+1u=1−u+11
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Integrate term-by-term:
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The integral of a constant is the constant times the variable of integration:
∫1du=u
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The integral of a constant times a function is the constant times the integral of the function:
∫(−u+11)du=−∫u+11du
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Let u=u+1.
Then let du=du and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(u+1)
So, the result is: −log(u+1)
The result is: u−log(u+1)
So, the result is: 2u−2log(u+1)
Now substitute u back in:
2x−2log(x+1)
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Add the constant of integration:
2x−2log(x+1)+constant
The answer is:
2x−2log(x+1)+constant
The answer (Indefinite)
[src]
/
|
| 1 / ___\ ___
| --------- dx = C - 2*log\1 + \/ x / + 2*\/ x
| ___
| \/ x + 1
|
/
∫x+11dx=C+2x−2log(x+1)
The graph
2−2log(2)
=
2−2log(2)
Use the examples entering the upper and lower limits of integration.