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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of 0dx
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Integral of x/(3x²-1)^4
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Integral of x^(4/5)
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Integral of (x^2)sinx
- 1/(x+y+2)^2
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Identical expressions
- one /(x+y+ two)^ two
- 1 divide by (x plus y plus 2) squared
- one divide by (x plus y plus two) to the power of two
- 1/(x+y+2)2
- 1/x+y+22
- 1/(x+y+2)²
- 1/(x+y+2) to the power of 2
- 1/x+y+2^2
- 1 divide by (x+y+2)^2
- 1/(x+y+2)^2dx
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Similar expressions
- 1/(x+y-2)^2
- 1/(x-y+2)^2
Integral of 1/(x+y+2)^2 dy
The solution
You have entered
[src]
1 / | | 1 | ------------ dy | 2 | (x + y + 2) | / 0
$$\int\limits_{0}^{1} \frac{1}{\left(\left(x + y\right) + 2\right)^{2}}\, dy$$
Integral(1/((x + y + 2)^2), (y, 0, 1))
The answer (Indefinite)
[src]
/ | | 1 1 | ------------ dy = C - --------- | 2 2 + x + y | (x + y + 2) | /
$$\int \frac{1}{\left(\left(x + y\right) + 2\right)^{2}}\, dy = C - \frac{1}{x + y + 2}$$
The answer
[src]
1 1 ----- - ----- 2 + x 3 + x
$$- \frac{1}{x + 3} + \frac{1}{x + 2}$$
=
=
1 1 ----- - ----- 2 + x 3 + x
$$- \frac{1}{x + 3} + \frac{1}{x + 2}$$
1/(2 + x) - 1/(3 + x)
Use the examples entering the upper and lower limits of integration.