Integral of 1/(x+2) dx

The solution

You have entered [src]

  1         
  /         
 |          
 |    1     
 |  ----- dx
 |  x + 2   
 |          
/           
0

$$\int\limits_{0}^{1} \frac{1}{x + 2}\, dx$$

Integral(1/(x + 2), (x, 0, 1))

Detail solution

Let $u = x + 2$ .

Then let $du = dx$ and substitute $du$ :

$\int \frac{1}{u}\, du$
1. The integral of $\frac{1}{u}$ is $\log{\left(u \right)}$ .
Now substitute $u$ back in:

$\log{\left(x + 2 \right)}$
Now simplify:

$\log{\left(x + 2 \right)}$
Add the constant of integration:

$\log{\left(x + 2 \right)}+ \mathrm{constant}$

The answer is:

$\log{\left(x + 2 \right)}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                         
 |                          
 |   1                      
 | ----- dx = C + log(x + 2)
 | x + 2                    
 |                          
/

$$\int \frac{1}{x + 2}\, dx = C + \log{\left(x + 2 \right)}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

-log(2) + log(3)

$$- \log{\left(2 \right)} + \log{\left(3 \right)}$$

-log(2) + log(3)

$$- \log{\left(2 \right)} + \log{\left(3 \right)}$$

-log(2) + log(3)

Numerical answer [src]

0.405465108108164

0.405465108108164

The graph

Use the examples entering the upper and lower limits of integration.

Other calculators

How to use it?

Identical expressions

Similar expressions

Integral of 1/(x+2) dx

Limits of integration:

The graph:

Piecewise:

The solution