Integral of 1/(x+3) dx
The solution
Detail solution
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Let u=x+3.
Then let du=dx and substitute du:
∫u1du
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The integral of u1 is log(u).
Now substitute u back in:
log(x+3)
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Now simplify:
log(x+3)
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Add the constant of integration:
log(x+3)+constant
The answer is:
log(x+3)+constant
The answer (Indefinite)
[src]
/
|
| 1
| ----- dx = C + log(x + 3)
| x + 3
|
/
∫x+31dx=C+log(x+3)
The graph
−log(3)+log(4)
=
−log(3)+log(4)
Use the examples entering the upper and lower limits of integration.