Integral of (1/x)+16*x*y^2 dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫16xy2dx=16y2∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: 8x2y2
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Don't know the steps in finding this integral.
But the integral is
log(x)
The result is: 8x2y2+log(x)
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Add the constant of integration:
8x2y2+log(x)+constant
The answer is:
8x2y2+log(x)+constant
The answer (Indefinite)
[src]
/
|
| / 1 2\ 2 2
| |1*- + 16*x*y | dx = C + 8*x *y + log(x)
| \ x /
|
/
8x2y2+logx
=
8y2+∞
Use the examples entering the upper and lower limits of integration.