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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of -exp(-3*x)
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Integral of 1/(x*(1-x))
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Integral of (x^3+1)^1/2
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Integral of (x^2)
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Identical expressions
- one /((x+ four)ln(x+ four))
- 1 divide by ((x plus 4)ln(x plus 4))
- one divide by ((x plus four)ln(x plus four))
- 1/x+4lnx+4
- 1 divide by ((x+4)ln(x+4))
- 1/((x+4)ln(x+4))dx
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Similar expressions
- 1/((x-4)ln(x+4))
- 1/((x+4)ln(x-4))
Integral of 1/((x+4)ln(x+4)) dx
The solution
You have entered
[src]
b / | | 1 | ------------------ dx | (x + 4)*log(x + 4) | / 1
$$\int\limits_{1}^{b} \frac{1}{\left(x + 4\right) \log{\left(x + 4 \right)}}\, dx$$
Integral(1/((x + 4)*log(x + 4)), (x, 1, b))
The answer (Indefinite)
[src]
/ | | 1 | ------------------ dx = C + log(log(4 + x)) | (x + 4)*log(x + 4) | /
$$\int \frac{1}{\left(x + 4\right) \log{\left(x + 4 \right)}}\, dx = C + \log{\left(\log{\left(x + 4 \right)} \right)}$$
The answer
[src]
-log(log(5)) + log(log(4 + b))
$$\log{\left(\log{\left(b + 4 \right)} \right)} - \log{\left(\log{\left(5 \right)} \right)}$$
=
=
-log(log(5)) + log(log(4 + b))
$$\log{\left(\log{\left(b + 4 \right)} \right)} - \log{\left(\log{\left(5 \right)} \right)}$$
-log(log(5)) + log(log(4 + b))
Use the examples entering the upper and lower limits of integration.