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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of e^(2*x+1)
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Integral of (1+x)/x
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Integral of -15x^2
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Integral of (1+x^4)^(1/2)
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Identical expressions
- (one /x)*(one /sqrt(one -(lnx)²))
- (1 divide by x) multiply by (1 divide by square root of (1 minus (lnx)²))
- (one divide by x) multiply by (one divide by square root of (one minus (lnx)²))
- (1/x)*(1/√(1-(lnx)²))
- (1/x)(1/sqrt(1-(lnx)²))
- 1/x1/sqrt1-lnx²
- (1 divide by x)*(1 divide by sqrt(1-(lnx)²))
- (1/x)*(1/sqrt(1-(lnx)²))dx
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Similar expressions
- (1/x)*(1/sqrt(1+(lnx)²))
Integral of (1/x)*(1/sqrt(1-(lnx)²)) dx
The solution
You have entered
[src]
1 / | | 1 | ------------------ dx | _____________ | / 2 | x*\/ 1 - log (x) | / 0
$$\int\limits_{0}^{1} \frac{1}{x \sqrt{1 - \log{\left(x \right)}^{2}}}\, dx$$
Integral(1/(x*sqrt(1 - log(x)^2)), (x, 0, 1))
The answer (Indefinite)
[src]
/ / | | | 1 | 1 | ------------------ dx = C + | --------------------------------- dx | _____________ | _____________________________ | / 2 | x*\/ -(1 + log(x))*(-1 + log(x)) | x*\/ 1 - log (x) | | / /
$$\int \frac{1}{x \sqrt{1 - \log{\left(x \right)}^{2}}}\, dx = C + \int \frac{1}{x \sqrt{- \left(\log{\left(x \right)} - 1\right) \left(\log{\left(x \right)} + 1\right)}}\, dx$$
The answer
[src]
1 / | | 1 | --------------------------------- dx | _____________________________ | x*\/ -(1 + log(x))*(-1 + log(x)) | / 0
$$\int\limits_{0}^{1} \frac{1}{x \sqrt{- \left(\log{\left(x \right)} - 1\right) \left(\log{\left(x \right)} + 1\right)}}\, dx$$
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1 / | | 1 | --------------------------------- dx | _____________________________ | x*\/ -(1 + log(x))*(-1 + log(x)) | / 0
$$\int\limits_{0}^{1} \frac{1}{x \sqrt{- \left(\log{\left(x \right)} - 1\right) \left(\log{\left(x \right)} + 1\right)}}\, dx$$
Integral(1/(x*sqrt(-(1 + log(x))*(-1 + log(x)))), (x, 0, 1))
Numerical answer
[src]
(1.39206658078322 - 5.06878125385943j)
(1.39206658078322 - 5.06878125385943j)
Use the examples entering the upper and lower limits of integration.