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How to use it?
- Integral of d{x}:
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Integral of 2x*e^x^2
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Integral of dx/(9*x^2-1)
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Integral of dx/(5-3*x)
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Integral of e^(2*x)*cos(3*x)*dx
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Identical expressions
- one /(x*(ln(x+ one))^ two)
- 1 divide by (x multiply by (ln(x plus 1)) squared )
- one divide by (x multiply by (ln(x plus one)) to the power of two)
- 1/(x*(ln(x+1))2)
- 1/x*lnx+12
- 1/(x*(ln(x+1))²)
- 1/(x*(ln(x+1)) to the power of 2)
- 1/(x(ln(x+1))^2)
- 1/(x(ln(x+1))2)
- 1/xlnx+12
- 1/xlnx+1^2
- 1 divide by (x*(ln(x+1))^2)
- 1/(x*(ln(x+1))^2)dx
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Similar expressions
- 1/(x*(ln(x-1))^2)
Integral of 1/(x*(ln(x+1))^2) dx
The solution
You have entered
[src]
oo / | | 1 | ------------- dx | 2 | x*log (x + 1) | / 1
$$\int\limits_{1}^{\infty} \frac{1}{x \log{\left(x + 1 \right)}^{2}}\, dx$$
Integral(1/(x*log(x + 1)^2), (x, 1, oo))
The answer (Indefinite)
[src]
/ / | | | 1 | 1 -1 - x | ------------- dx = C - | ------------- dx + ------------ | 2 | 2 x*log(1 + x) | x*log (x + 1) | x *log(1 + x) | | / /
$$\int \frac{1}{x \log{\left(x + 1 \right)}^{2}}\, dx = C - \int \frac{1}{x^{2} \log{\left(x + 1 \right)}}\, dx + \frac{- x - 1}{x \log{\left(x + 1 \right)}}$$
The answer
[src]
oo
/
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| 1 2
- | ------------- dx + ------
| 2 log(2)
| x *log(1 + x)
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1
$$- \int\limits_{1}^{\infty} \frac{1}{x^{2} \log{\left(x + 1 \right)}}\, dx + \frac{2}{\log{\left(2 \right)}}$$
=
=
oo
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| 1 2
- | ------------- dx + ------
| 2 log(2)
| x *log(1 + x)
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/
1
$$- \int\limits_{1}^{\infty} \frac{1}{x^{2} \log{\left(x + 1 \right)}}\, dx + \frac{2}{\log{\left(2 \right)}}$$
-Integral(1/(x^2*log(1 + x)), (x, 1, oo)) + 2/log(2)
Use the examples entering the upper and lower limits of integration.