Integral of 1/((sqrtx-1)x^2) dx
The solution
Detail solution
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There are multiple ways to do this integral.
Method #1
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Rewrite the integrand:
x2(x−1)1=−−x25+x21
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The integral of a constant times a function is the constant times the integral of the function:
∫(−−x25+x21)dx=−∫−x25+x21dx
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Don't know the steps in finding this integral.
But the integral is
log(x)−2log(x−1)−x1−x2
So, the result is: −log(x)+2log(x−1)+x1+x2
Method #2
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Rewrite the integrand:
x2(x−1)1=x25−x21
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Rewrite the integrand:
x25−x21=−−x25+x21
-
The integral of a constant times a function is the constant times the integral of the function:
∫(−−x25+x21)dx=−∫−x25+x21dx
-
Don't know the steps in finding this integral.
But the integral is
log(x)−2log(x−1)−x1−x2
So, the result is: −log(x)+2log(x−1)+x1+x2
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Add the constant of integration:
−log(x)+2log(x−1)+x1+x2+constant
The answer is:
−log(x)+2log(x−1)+x1+x2+constant
The answer (Indefinite)
[src]
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| 1 1 2 / ___\
| -------------- dx = C + - - log(x) + ----- + 2*log\-1 + \/ x /
| / ___ \ 2 x ___
| \\/ x - 1/*x \/ x
|
/
∫x2(x−1)1dx=C−log(x)+2log(x−1)+x1+x2
Use the examples entering the upper and lower limits of integration.