Integral of 1/sqrt(10-3x) dx
The solution
Detail solution
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Let u=10−3x.
Then let du=−210−3x3dx and substitute −32du:
∫(−32)du
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The integral of a constant times a function is the constant times the integral of the function:
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The integral of a constant is the constant times the variable of integration:
∫1du=u
So, the result is: −32u
Now substitute u back in:
−3210−3x
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Add the constant of integration:
−3210−3x+constant
The answer is:
−3210−3x+constant
The answer (Indefinite)
[src]
/
| __________
| 1 2*\/ 10 - 3*x
| ------------ dx = C - --------------
| __________ 3
| \/ 10 - 3*x
|
/
∫10−3x1dx=C−3210−3x
The graph
Use the examples entering the upper and lower limits of integration.