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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of sin^2(x)cos^2(x)
- Integral of x^2√(1-x^2)
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Integral of exp(y)
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Integral of 1/(2+cos(x))
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Identical expressions
- one /(sin(4x- one)^ two)
- 1 divide by ( sinus of (4x minus 1) squared )
- one divide by ( sinus of (4x minus one) to the power of two)
- 1/(sin(4x-1)2)
- 1/sin4x-12
- 1/(sin(4x-1)²)
- 1/(sin(4x-1) to the power of 2)
- 1/sin4x-1^2
- 1 divide by (sin(4x-1)^2)
- 1/(sin(4x-1)^2)dx
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Similar expressions
- 1/(sin(4x+1)^2)
Integral of 1/(sin(4x-1)^2) dx
The solution
You have entered
[src]
1 / | | 1 | ------------- dx | 2 | sin (4*x - 1) | / 0
$$\int\limits_{0}^{1} \frac{1}{\sin^{2}{\left(4 x - 1 \right)}}\, dx$$
Integral(1/(sin(4*x - 1)^2), (x, 0, 1))
The answer (Indefinite)
[src]
/ | | 1 1 tan(-1/2 + 2*x) | ------------- dx = C - ----------------- + --------------- | 2 8*tan(-1/2 + 2*x) 8 | sin (4*x - 1) | /
$$\int \frac{1}{\sin^{2}{\left(4 x - 1 \right)}}\, dx = C + \frac{\tan{\left(2 x - \frac{1}{2} \right)}}{8} - \frac{1}{8 \tan{\left(2 x - \frac{1}{2} \right)}}$$
The graph
The answer
[src]
1 / | | 1 | -------------- dx | 2 | sin (-1 + 4*x) | / 0
$$\int\limits_{0}^{1} \frac{1}{\sin^{2}{\left(4 x - 1 \right)}}\, dx$$
=
=
1 / | | 1 | -------------- dx | 2 | sin (-1 + 4*x) | / 0
$$\int\limits_{0}^{1} \frac{1}{\sin^{2}{\left(4 x - 1 \right)}}\, dx$$
Integral(sin(-1 + 4*x)^(-2), (x, 0, 1))
Use the examples entering the upper and lower limits of integration.