Integral of (1/sin²x-4x) dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫(−4x)dx=−4∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: −2x2
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Don't know the steps in finding this integral.
But the integral is
−sin(x)cos(x)
The result is: −2x2−sin(x)cos(x)
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Now simplify:
−2x2−tan(x)1
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Add the constant of integration:
−2x2−tan(x)1+constant
The answer is:
−2x2−tan(x)1+constant
The answer (Indefinite)
[src]
/
|
| / 1 \ 2 cos(x)
| |------- - 4*x| dx = C - 2*x - ------
| | 2 | sin(x)
| \sin (x) /
|
/
∫(−4x+sin2(x)1)dx=C−2x2−sin(x)cos(x)
The graph
Use the examples entering the upper and lower limits of integration.