oo / | | 1 | ---------- dx | log(x + 1) | / 0
Integral(1/log(x + 1), (x, 0, oo))
LiRule(a=1, b=1, context=1/log(x + 1), symbol=x)
Add the constant of integration:
The answer is:
/ | | 1 | ---------- dx = C + li(1 + x) | log(x + 1) | /
Use the examples entering the upper and lower limits of integration.