Integral of 1/(5-4cos(2x)) dx
The solution
Detail solution
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Rewrite the integrand:
1⋅5−4cos(2x)1=−4cos(2x)−51
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The integral of a constant times a function is the constant times the integral of the function:
∫(−4cos(2x)−51)dx=−∫4cos(2x)−51dx
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Don't know the steps in finding this integral.
But the integral is
−3atan(3tan(x))−3π⌊πx−2π⌋
So, the result is: 3atan(3tan(x))+3π⌊πx−2π⌋
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Now simplify:
3atan(3tan(x))+3π⌊πx−21⌋
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Add the constant of integration:
3atan(3tan(x))+3π⌊πx−21⌋+constant
The answer is:
3atan(3tan(x))+3π⌊πx−21⌋+constant
The answer (Indefinite)
[src]
/ pi\
|x - --|
/ | 2 |
| pi*floor|------|
| 1 atan(3*tan(x)) \ pi /
| 1*-------------- dx = C + -------------- + ----------------
| 5 - 4*cos(2*x) 3 3
|
/
3arctan(cos(2x)+13sin(2x))
The graph
atan(3*tan(1))
--------------
3
3arctan(cos2+13sin2)
=
atan(3*tan(1))
--------------
3
3atan(3tan(1))
Use the examples entering the upper and lower limits of integration.