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- Improper integral
- Double Integral
- Triple Integral
- Curvilinear integral
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How to use it?
- Integral of d{x}:
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Integral of -e^x
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Integral of -15x^2
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Integral of xe^(1-x)
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Integral of -xe^x
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Identical expressions
- one /(cos^ three (x))
- 1 divide by ( co sinus of e of cubed (x))
- one divide by ( co sinus of e of to the power of three (x))
- 1/(cos3(x))
- 1/cos3x
- 1/(cos³(x))
- 1/(cos to the power of 3(x))
- 1/cos^3x
- 1 divide by (cos^3(x))
- 1/(cos^3(x))dx
Integral of 1/(cos^3(x)) dx
The solution
You have entered
[src]
1 / | | 1 | 1*------- dx | 3 | cos (x) | / 0
$$\int\limits_{0}^{1} 1 \cdot \frac{1}{\cos^{3}{\left(x \right)}}\, dx$$
Integral(1/cos(x)^3, (x, 0, 1))
The answer (Indefinite)
[src]
/ | | 1 log(-1 + sin(x)) log(1 + sin(x)) sin(x) | 1*------- dx = C - ---------------- + --------------- - -------------- | 3 4 4 2 | cos (x) -2 + 2*sin (x) | /
$${{\log \left(\sin x+1\right)}\over{4}}-{{\log \left(\sin x-1\right)
}\over{4}}-{{\sin x}\over{2\,\sin ^2x-2}}$$
The graph
The answer
[src]
log(1 - sin(1)) log(1 + sin(1)) sin(1)
- --------------- + --------------- - --------------
4 4 2
-2 + 2*sin (1)
$${{\log \left(\sin 1+1\right)}\over{4}}-{{\log \left(1-\sin 1\right)
}\over{4}}-{{\sin 1}\over{2\,\sin ^21-2}}$$
=
=
log(1 - sin(1)) log(1 + sin(1)) sin(1)
- --------------- + --------------- - --------------
4 4 2
-2 + 2*sin (1)
$$\frac{\log{\left(\sin{\left(1 \right)} + 1 \right)}}{4} - \frac{\log{\left(- \sin{\left(1 \right)} + 1 \right)}}{4} - \frac{\sin{\left(1 \right)}}{-2 + 2 \sin^{2}{\left(1 \right)}}$$
The graph
Use the examples entering the upper and lower limits of integration.