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- Improper integral
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How to use it?
- Integral of d{x}:
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Integral of x^4/(1-x^2)
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Integral of 6/x^2
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Integral of √(x+4)
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Integral of sin(2x)cos(2x)
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Identical expressions
- one /cos^2x√(2tgx- one)
- 1 divide by co sinus of e of squared x√(2tgx minus 1)
- one divide by co sinus of e of squared x√(2tgx minus one)
- 1/cos2x√(2tgx-1)
- 1/cos2x√2tgx-1
- 1/cos²x√(2tgx-1)
- 1/cos to the power of 2x√(2tgx-1)
- 1/cos^2x√2tgx-1
- 1 divide by cos^2x√(2tgx-1)
- 1/cos^2x√(2tgx-1)dx
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Similar expressions
- 1/cos^2x√(2tgx+1)
Integral of 1/cos^2x√(2tgx-1) dx
The solution
You have entered
[src]
1 / | | ______________ | \/ 2*tan(x) - 1 | ---------------- dx | 2 | cos (x) | / 0
$$\int\limits_{0}^{1} \frac{\sqrt{2 \tan{\left(x \right)} - 1}}{\cos^{2}{\left(x \right)}}\, dx$$
Integral(sqrt(2*tan(x) - 1)/cos(x)^2, (x, 0, 1))
The answer (Indefinite)
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/ / | | | ______________ | _______________ | \/ 2*tan(x) - 1 | \/ -1 + 2*tan(x) | ---------------- dx = C + | ----------------- dx | 2 | 2 | cos (x) | cos (x) | | / /
$$\int \frac{\sqrt{2 \tan{\left(x \right)} - 1}}{\cos^{2}{\left(x \right)}}\, dx = C + \int \frac{\sqrt{2 \tan{\left(x \right)} - 1}}{\cos^{2}{\left(x \right)}}\, dx$$
The answer
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1 / | | _______________ | \/ -1 + 2*tan(x) | ----------------- dx | 2 | cos (x) | / 0
$$\int\limits_{0}^{1} \frac{\sqrt{2 \tan{\left(x \right)} - 1}}{\cos^{2}{\left(x \right)}}\, dx$$
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1 / | | _______________ | \/ -1 + 2*tan(x) | ----------------- dx | 2 | cos (x) | / 0
$$\int\limits_{0}^{1} \frac{\sqrt{2 \tan{\left(x \right)} - 1}}{\cos^{2}{\left(x \right)}}\, dx$$
Integral(sqrt(-1 + 2*tan(x))/cos(x)^2, (x, 0, 1))
Numerical answer
[src]
(1.02465872239267 + 0.333202573561059j)
(1.02465872239267 + 0.333202573561059j)
Use the examples entering the upper and lower limits of integration.