Integral of 6/x^2 dx

1. The integral of a constant times a function is the constant times the integral of the function:

   $$\int \frac{6}{x^{2}}\, dx = 6 \int \frac{1}{x^{2}}\, dx$$

   1. Rewrite the integrand:

      $$\frac{1}{x^{2}} = \tilde{\infty} 0$$

   2. The integral of a constant times a function is the constant times the integral of the function:

      $$\int \tilde{\infty} 0\, dx = \tilde{\infty} \int 0\, dx$$

      1. Integrate term-by-term:

         1. The integral of $\frac{1}{x}$ is $\log{\left(x \right)}$.

         1. The integral of a constant times a function is the constant times the integral of the function:

            $$\int \left(- \frac{1}{x}\right)\, dx = - \int \frac{1}{x}\, dx$$

            1. The integral of $\frac{1}{x}$ is $\log{\left(x \right)}$.

            So, the result is: $- \log{\left(x \right)}$

         The result is: $0$

      So, the result is: $\text{NaN}$

   So, the result is: $\text{NaN}$

2. Add the constant of integration:

   $$\text{NaN}+ \mathrm{constant}$$

The answer is: