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-x^2+6x-5

Integral of -x^2+6x-5 dx

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12((x2+6x)5)dx\int\limits_{1}^{2} \left(\left(- x^{2} + 6 x\right) - 5\right)\, dx
Integral(-x^2 + 6*x - 5, (x, 1, 2))
Detail solution
  1. Integrate term-by-term:

    1. Integrate term-by-term:

      1. The integral of a constant times a function is the constant times the integral of the function:

        (x2)dx=x2dx\int \left(- x^{2}\right)\, dx = - \int x^{2}\, dx

        1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n1n \neq -1:

          x2dx=x33\int x^{2}\, dx = \frac{x^{3}}{3}

        So, the result is: x33- \frac{x^{3}}{3}

      1. The integral of a constant times a function is the constant times the integral of the function:

        6xdx=6xdx\int 6 x\, dx = 6 \int x\, dx

        1. The integral of xnx^{n} is xn+1n+1\frac{x^{n + 1}}{n + 1} when n1n \neq -1:

          xdx=x22\int x\, dx = \frac{x^{2}}{2}

        So, the result is: 3x23 x^{2}

      The result is: x33+3x2- \frac{x^{3}}{3} + 3 x^{2}

    1. The integral of a constant is the constant times the variable of integration:

      (5)dx=5x\int \left(-5\right)\, dx = - 5 x

    The result is: x33+3x25x- \frac{x^{3}}{3} + 3 x^{2} - 5 x

  2. Now simplify:

    x(x2+9x15)3\frac{x \left(- x^{2} + 9 x - 15\right)}{3}

  3. Add the constant of integration:

    x(x2+9x15)3+constant\frac{x \left(- x^{2} + 9 x - 15\right)}{3}+ \mathrm{constant}


The answer is:

x(x2+9x15)3+constant\frac{x \left(- x^{2} + 9 x - 15\right)}{3}+ \mathrm{constant}

The answer (Indefinite) [src]
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 | \- x  + 6*x - 5/ dx = C - 5*x + 3*x  - --
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((x2+6x)5)dx=Cx33+3x25x\int \left(\left(- x^{2} + 6 x\right) - 5\right)\, dx = C - \frac{x^{3}}{3} + 3 x^{2} - 5 x
The graph
1.002.001.101.201.301.401.501.601.701.801.905-5
The answer [src]
5/3
53\frac{5}{3}
=
=
5/3
53\frac{5}{3}
5/3
Numerical answer [src]
1.66666666666667
1.66666666666667
The graph
Integral of -x^2+6x-5 dx

    Use the examples entering the upper and lower limits of integration.