Integral of -x^2+6x-5 dx
The solution
Detail solution
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Integrate term-by-term:
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫(−x2)dx=−∫x2dx
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The integral of xn is n+1xn+1 when n=−1:
∫x2dx=3x3
So, the result is: −3x3
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The integral of a constant times a function is the constant times the integral of the function:
∫6xdx=6∫xdx
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The integral of xn is n+1xn+1 when n=−1:
∫xdx=2x2
So, the result is: 3x2
The result is: −3x3+3x2
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The integral of a constant is the constant times the variable of integration:
∫(−5)dx=−5x
The result is: −3x3+3x2−5x
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Now simplify:
3x(−x2+9x−15)
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Add the constant of integration:
3x(−x2+9x−15)+constant
The answer is:
3x(−x2+9x−15)+constant
The answer (Indefinite)
[src]
/
| 3
| / 2 \ 2 x
| \- x + 6*x - 5/ dx = C - 5*x + 3*x - --
| 3
/
∫((−x2+6x)−5)dx=C−3x3+3x2−5x
The graph
Use the examples entering the upper and lower limits of integration.