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Integral of -1/2 dt

Limits of integration:

from to
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The graph:

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Piecewise:

The solution

You have entered [src] 
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 |  -1/2 dt
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∫01(−12) dt\int\limits_{0}^{1} \left(- \frac{1}{2}\right)\, dt 
Integral(-1/2, (t, 0, 1))
Detail solution

  1. The integral of a constant is the constant times the variable of integration:

    ∫(−12) dt=−t2\int \left(- \frac{1}{2}\right)\, dt = - \frac{t}{2}

  2. Add the constant of integration:

    −t2+constant- \frac{t}{2}+ \mathrm{constant}

The answer is:

−t2+constant- \frac{t}{2}+ \mathrm{constant}

The answer (Indefinite) [src] 
  /               
 |               t
 | -1/2 dt = C - -
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∫(−12) dt=C−t2\int \left(- \frac{1}{2}\right)\, dt = C - \frac{t}{2}
Simplify
The graph
0.001.000.100.200.300.400.500.600.700.800.90-1.00.5
Plot the graph f(x)
The answer [src] 
-1/2
−12- \frac{1}{2} 
=
= 
-1/2
−12- \frac{1}{2} 
-1/2
Numerical answer [src] 
-0.5
-0.5
The graph
Integral of -1/2 dt

    Use the examples entering the upper and lower limits of integration.

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