Integral of exp(x)*sin(x) dx
The solution
Detail solution
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Use integration by parts, noting that the integrand eventually repeats itself.
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For the integrand exsin(x):
Let u(x)=sin(x) and let dv(x)=ex.
Then ∫exsin(x)dx=exsin(x)−∫excos(x)dx.
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For the integrand excos(x):
Let u(x)=cos(x) and let dv(x)=ex.
Then ∫exsin(x)dx=exsin(x)−excos(x)+∫(−exsin(x))dx.
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Notice that the integrand has repeated itself, so move it to one side:
2∫exsin(x)dx=exsin(x)−excos(x)
Therefore,
∫exsin(x)dx=2exsin(x)−2excos(x)
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Now simplify:
−22excos(x+4π)
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Add the constant of integration:
−22excos(x+4π)+constant
The answer is:
−22excos(x+4π)+constant
The answer (Indefinite)
[src]
/
| x x
| x e *sin(x) cos(x)*e
| e *sin(x) dx = C + --------- - ---------
| 2 2
/
2ex(sinx−cosx)
The graph
1 e*sin(1) e*cos(1)
- + -------- - --------
2 2 2
2esin1−ecos1+21
=
1 e*sin(1) e*cos(1)
- + -------- - --------
2 2 2
−2ecos(1)+21+2esin(1)
Use the examples entering the upper and lower limits of integration.