Integral of e^(-4x) dx
The solution
Detail solution
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Let u=−4x.
Then let du=−4dx and substitute −4du:
∫(−4eu)du
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The integral of a constant times a function is the constant times the integral of the function:
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The integral of the exponential function is itself.
∫eudu=eu
So, the result is: −4eu
Now substitute u back in:
−4e−4x
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Add the constant of integration:
−4e−4x+constant
The answer is:
−4e−4x+constant
The answer (Indefinite)
[src]
/
| -4*x
| -4*x e
| E dx = C - -----
| 4
/
∫e−4xdx=C−4e−4x
The graph
41−4e41
=
41−4e41
Use the examples entering the upper and lower limits of integration.