Integral of e^(5x)*sin(x) dx
The solution
Detail solution
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Use integration by parts, noting that the integrand eventually repeats itself.
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For the integrand e5xsin(x):
Let u(x)=sin(x) and let dv(x)=e5x.
Then ∫e5xsin(x)dx=5e5xsin(x)−∫5e5xcos(x)dx.
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For the integrand 5e5xcos(x):
Let u(x)=5cos(x) and let dv(x)=e5x.
Then ∫e5xsin(x)dx=5e5xsin(x)−25e5xcos(x)+∫(−25e5xsin(x))dx.
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Notice that the integrand has repeated itself, so move it to one side:
2526∫e5xsin(x)dx=5e5xsin(x)−25e5xcos(x)
Therefore,
∫e5xsin(x)dx=265e5xsin(x)−26e5xcos(x)
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Now simplify:
26(5sin(x)−cos(x))e5x
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Add the constant of integration:
26(5sin(x)−cos(x))e5x+constant
The answer is:
26(5sin(x)−cos(x))e5x+constant
The answer (Indefinite)
[src]
/
| 5*x 5*x
| 5*x cos(x)*e 5*e *sin(x)
| e *sin(x) dx = C - ----------- + -------------
| 26 26
/
26e5x(5sinx−cosx)
The graph
5 5
1 cos(1)*e 5*e *sin(1)
-- - --------- + -----------
26 26 26
265e5sin1−e5cos1+261
=
5 5
1 cos(1)*e 5*e *sin(1)
-- - --------- + -----------
26 26 26
−26e5cos(1)+261+265e5sin(1)
Use the examples entering the upper and lower limits of integration.