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- Improper integral
- Double Integral
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How to use it?
- Integral of d{x}:
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Integral of sin(x)*dx/x
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Integral of 1/sqrt(x^2+1)
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Integral of x^3*ln(x)
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Integral of x*ln(x+1)dx
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Identical expressions
- (dx)/(x(ln^2x+ one))
- (dx) divide by (x(ln squared x plus 1))
- (dx) divide by (x(ln squared x plus one))
- (dx)/(x(ln2x+1))
- dx/xln2x+1
- (dx)/(x(ln²x+1))
- (dx)/(x(ln to the power of 2x+1))
- dx/xln^2x+1
- (dx) divide by (x(ln^2x+1))
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Similar expressions
- (dx)/(x(ln^2x-1))
Integral of (dx)/(x(ln^2x+1)) dx
The solution
You have entered
[src]
0 / | | 1 | --------------- dx | / 2 \ | x*\log (x) + 1/ | / 0
$$\int\limits_{0}^{0} \frac{1}{x \left(\log{\left(x \right)}^{2} + 1\right)}\, dx$$
Integral(1/(x*(log(x)^2 + 1)), (x, 0, 0))
The answer (Indefinite)
[src]
/ | | 1 / 2 \ | --------------- dx = C + RootSum\4*z + 1, i -> i*log(2*i + log(x))/ | / 2 \ | x*\log (x) + 1/ | /
$$\int \frac{1}{x \left(\log{\left(x \right)}^{2} + 1\right)}\, dx = C + \operatorname{RootSum} {\left(4 z^{2} + 1, \left( i \mapsto i \log{\left(2 i + \log{\left(x \right)} \right)} \right)\right)}$$
Use the examples entering the upper and lower limits of integration.