E / | | 1 | ----- du | u + 1 | / 1
Integral(1/(u + 1), (u, 1, E))
Let .
Then let and substitute :
The integral of is .
Now substitute back in:
Now simplify:
Add the constant of integration:
The answer is:
/ | | 1 | ----- du = C + log(u + 1) | u + 1 | /
-log(2) + log(1 + E)
=
-log(2) + log(1 + E)
-log(2) + log(1 + E)
Use the examples entering the upper and lower limits of integration.