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How to use it?
- Integral of d{x}:
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Integral of sin²xcos²x
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Integral of ex^2
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Integral of -e^x
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Integral of (1+2x^2)/(x^2(1+x^2))
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Identical expressions
- cosx/(one +x^ two)
- co sinus of e of x divide by (1 plus x squared )
- co sinus of e of x divide by (one plus x to the power of two)
- cosx/(1+x2)
- cosx/1+x2
- cosx/(1+x²)
- cosx/(1+x to the power of 2)
- cosx/1+x^2
- cosx divide by (1+x^2)
- cosx/(1+x^2)dx
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Similar expressions
- cosx/(1-x^2)
Integral of cosx/(1+x^2) dx
The solution
You have entered
[src]
1 / | | cos(x) | ------ dx | 2 | 1 + x | / 0
$$\int\limits_{0}^{1} \frac{\cos{\left(x \right)}}{x^{2} + 1}\, dx$$
Integral(cos(x)/(1 + x^2), (x, 0, 1))
The answer (Indefinite)
[src]
/ / | | | cos(x) | cos(x) | ------ dx = C + | ------ dx | 2 | 2 | 1 + x | 1 + x | | / /
$$\int {{{\cos x}\over{x^2+1}}}{\;dx}$$
The answer
[src]
1 / | | cos(x) | ------ dx | 2 | 1 + x | / 0
$$\int_{0}^{1}{{{\cos x}\over{x^2+1}}\;dx}$$
=
=
1 / | | cos(x) | ------ dx | 2 | 1 + x | / 0
$$\int\limits_{0}^{1} \frac{\cos{\left(x \right)}}{x^{2} + 1}\, dx$$
Use the examples entering the upper and lower limits of integration.