Integral of cos^2(5x) dx
The solution
Detail solution
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Rewrite the integrand:
cos2(5x)=2cos(10x)+21
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫2cos(10x)dx=2∫cos(10x)dx
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Let u=10x.
Then let du=10dx and substitute 10du:
∫100cos(u)du
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The integral of a constant times a function is the constant times the integral of the function:
∫10cos(u)du=10∫cos(u)du
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The integral of cosine is sine:
∫cos(u)du=sin(u)
So, the result is: 10sin(u)
Now substitute u back in:
10sin(10x)
So, the result is: 20sin(10x)
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The integral of a constant is the constant times the variable of integration:
∫21dx=2x
The result is: 2x+20sin(10x)
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Add the constant of integration:
2x+20sin(10x)+constant
The answer is:
2x+20sin(10x)+constant
The answer (Indefinite)
[src]
/
|
| 2 x sin(10*x)
| cos (5*x) dx = C + - + ---------
| 2 20
/
102sin(10x)+5x
The graph
1 cos(5)*sin(5)
- + -------------
2 10
20sin10+10
=
1 cos(5)*sin(5)
- + -------------
2 10
10sin(5)cos(5)+21
Use the examples entering the upper and lower limits of integration.