Integral of cos^2t*sint dx
The solution
Detail solution
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Let u=cos(t).
Then let du=−sin(t)dt and substitute −du:
∫u2du
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The integral of a constant times a function is the constant times the integral of the function:
∫(−u2)du=−∫u2du
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The integral of un is n+1un+1 when n=−1:
∫u2du=3u3
So, the result is: −3u3
Now substitute u back in:
−3cos3(t)
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Add the constant of integration:
−3cos3(t)+constant
The answer is:
−3cos3(t)+constant
The answer (Indefinite)
[src]
/
| 3
| 2 cos (t)
| cos (t)*sin(t) dt = C - -------
| 3
/
−3cos3t
The graph
3
1 cos (1)
- - -------
3 3
31−3cos31
=
3
1 cos (1)
- - -------
3 3
−3cos3(1)+31
Use the examples entering the upper and lower limits of integration.