Integral of (cos(lnx))/x dx

The solution

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  1               
  /               
 |                
 |  cos(log(x))   
 |  ----------- dx
 |       x        
 |                
/                 
0

$$\int\limits_{0}^{1} \frac{\cos{\left(\log{\left(x \right)} \right)}}{x}\, dx$$

Integral(cos(log(x))/x, (x, 0, 1))

Detail solution

There are multiple ways to do this integral.
Method #1
1. Let $u = \log{\left(x \right)}$ .
  
  Then let $du = \frac{dx}{x}$ and substitute $du$ :
  
  $\int \cos{\left(u \right)}\, du$
  1. The integral of cosine is sine:
    
    $\int \cos{\left(u \right)}\, du = \sin{\left(u \right)}$
  Now substitute $u$ back in:
  
  $\sin{\left(\log{\left(x \right)} \right)}$
Method #2
1. Let $u = \frac{1}{x}$ .
  
  Then let $du = - \frac{dx}{x^{2}}$ and substitute $- du$ :
  
  $\int \frac{\cos{\left(\log{\left(\frac{1}{u} \right)} \right)}}{u}\, du$
  1. The integral of a constant times a function is the constant times the integral of the function:
    
    $\int \left(- \frac{\cos{\left(\log{\left(\frac{1}{u} \right)} \right)}}{u}\right)\, du = - \int \frac{\cos{\left(\log{\left(\frac{1}{u} \right)} \right)}}{u}\, du$
    1. Let $u = \log{\left(\frac{1}{u} \right)}$ .
      
      Then let $du = - \frac{du}{u}$ and substitute $- du$ :
      
      $\int \cos{\left(u \right)}\, du$
      
      The integral of a constant times a function is the constant times the integral of the function:
      
      $\int \left(- \cos{\left(u \right)}\right)\, du = - \int \cos{\left(u \right)}\, du$
      
      The integral of cosine is sine:
      
      $\int \cos{\left(u \right)}\, du = \sin{\left(u \right)}$
      
      So, the result is: $- \sin{\left(u \right)}$
      
      Now substitute $u$ back in:
      
      $- \sin{\left(\log{\left(\frac{1}{u} \right)} \right)}$
    So, the result is: $\sin{\left(\log{\left(\frac{1}{u} \right)} \right)}$
  Now substitute $u$ back in:
  
  $\sin{\left(\log{\left(x \right)} \right)}$
Add the constant of integration:

$\sin{\left(\log{\left(x \right)} \right)}+ \mathrm{constant}$

The answer is:

$\sin{\left(\log{\left(x \right)} \right)}+ \mathrm{constant}$

The answer (Indefinite) [src]

  /                                
 |                                 
 | cos(log(x))                     
 | ----------- dx = C + sin(log(x))
 |      x                          
 |                                 
/

$$\sin \log x$$

Simplify

The answer [src]

<-1, 1>

$$\int_{0}^{1}{{{\cos \log x}\over{x}}\;dx}$$

<-1, 1>

$$\left\langle -1, 1\right\rangle$$

Simplify

Numerical answer [src]

0.110056905018961

0.110056905018961

Use the examples entering the upper and lower limits of integration.

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Identical expressions

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Integral of (cos(lnx))/x dx

Limits of integration:

The graph:

Piecewise:

The solution

Method #1

Method #2