Integral of cos(100x+2)dx dx
The solution
Detail solution
-
Let u=100x+2.
Then let du=100dx and substitute 100du:
∫100cos(u)du
-
The integral of a constant times a function is the constant times the integral of the function:
∫cos(u)du=100∫cos(u)du
-
The integral of cosine is sine:
∫cos(u)du=sin(u)
So, the result is: 100sin(u)
Now substitute u back in:
100sin(100x+2)
-
Now simplify:
100sin(100x+2)
-
Add the constant of integration:
100sin(100x+2)+constant
The answer is:
100sin(100x+2)+constant
The answer (Indefinite)
[src]
/
| sin(100*x + 2)
| cos(100*x + 2) dx = C + --------------
| 100
/
∫cos(100x+2)dx=C+100sin(100x+2)
The graph
sin(2) sin(102)
- ------ + --------
100 100
−100sin(2)+100sin(102)
=
sin(2) sin(102)
- ------ + --------
100 100
−100sin(2)+100sin(102)
-sin(2)/100 + sin(102)/100
Use the examples entering the upper and lower limits of integration.