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How to use it?
- Integral of d{x}:
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Integral of 1/
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Integral of dy/y^2
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Integral of x/x
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Integral of x/cos^2x
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Identical expressions
- arctgx^ two x/(one +x^2)
- arctgx squared x divide by (1 plus x squared )
- arctgx to the power of two x divide by (one plus x squared )
- arctgx2x/(1+x2)
- arctgx2x/1+x2
- arctgx²x/(1+x²)
- arctgx to the power of 2x/(1+x to the power of 2)
- arctgx^2x/1+x^2
- arctgx^2x divide by (1+x^2)
- arctgx^2x/(1+x^2)dx
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Similar expressions
- arctgx^2x/(1-x^2)
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What you mean?
- acot(x)^2*x/(1 + x^2)
- acot(x)^(2*x)/(1 + x^2)
- acot(x)^(2*x)/(1 + x^2)
You entered:
arctgx^2x/(1+x^2)
What you mean?
Integral of arctgx^2x/(1+x^2) dx
The solution
You have entered
[src]
1 / | | 2 | acot (x)*x | ---------- dx | 2 | 1 + x | / 0
$$\int\limits_{0}^{1} \frac{x \operatorname{acot}^{2}{\left(x \right)}}{x^{2} + 1}\, dx$$
Integral(acot(x)^2*x/(1 + x^2), (x, 0, 1))
The answer (Indefinite)
[src]
/ / | | | 2 | 2 | acot (x)*x | x*acot (x) | ---------- dx = C + | ---------- dx | 2 | 2 | 1 + x | 1 + x | | / /
$$\int {{{x\,\left({\rm arccot}\; x\right)^2}\over{x^2+1}}}{\;dx}$$
The answer
[src]
1 / | | 2 | x*acot (x) | ---------- dx | 2 | 1 + x | / 0
$$\int_{0}^{1}{{{x\,\left({\rm arccot}\; x\right)^2}\over{x^2+1}}\;dx
}$$
=
=
1 / | | 2 | x*acot (x) | ---------- dx | 2 | 1 + x | / 0
$$\int\limits_{0}^{1} \frac{x \operatorname{acot}^{2}{\left(x \right)}}{x^{2} + 1}\, dx$$
Use the examples entering the upper and lower limits of integration.