Integral of (8x^3+1) dx
The solution
Detail solution
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Integrate term-by-term:
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The integral of a constant times a function is the constant times the integral of the function:
∫8x3dx=8∫x3dx
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The integral of xn is n+1xn+1 when n=−1:
∫x3dx=4x4
So, the result is: 2x4
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The integral of a constant is the constant times the variable of integration:
∫1dx=x
The result is: 2x4+x
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Add the constant of integration:
2x4+x+constant
The answer is:
2x4+x+constant
The answer (Indefinite)
[src]
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| / 3 \ 4
| \8*x + 1/ dx = C + x + 2*x
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∫(8x3+1)dx=C+2x4+x
The graph
Use the examples entering the upper and lower limits of integration.