Integral of 8cosx dx

1. The integral of a constant times a function is the constant times the integral of the function:

   $$\int 8 \cos{\left(x \right)}\, dx = 8 \int \cos{\left(x \right)}\, dx$$

   1. The integral of cosine is sine:

      $$\int \cos{\left(x \right)}\, dx = \sin{\left(x \right)}$$

   So, the result is: $8 \sin{\left(x \right)}$

2. Add the constant of integration:

   $$8 \sin{\left(x \right)}+ \mathrm{constant}$$

The answer is:

$$8 \sin{\left(x \right)}+ \mathrm{constant}$$