Integral of (80cosx)*(sin^3(x)) dx
The solution
Detail solution
-
Let u=sin(x).
Then let du=cos(x)dx and substitute 80du:
∫80u3du
-
The integral of a constant times a function is the constant times the integral of the function:
∫u3du=80∫u3du
-
The integral of un is n+1un+1 when n=−1:
∫u3du=4u4
So, the result is: 20u4
Now substitute u back in:
20sin4(x)
-
Add the constant of integration:
20sin4(x)+constant
The answer is:
20sin4(x)+constant
The answer (Indefinite)
[src]
/
|
| 3 4
| 80*cos(x)*sin (x) dx = C + 20*sin (x)
|
/
∫sin3(x)80cos(x)dx=C+20sin4(x)
The graph
Use the examples entering the upper and lower limits of integration.